Preparation of 0.5 Normal NaOH and 1 gm Dextrose Solution

To prepare a 0.5 N NaOH solution, we need to calculate the amount of sodium hydroxide (NaOH) required. Formula for normality(N) = Weight of solute (g)/ Equivalent weight of solute (g/equiv) X Volume of solution (L) Step 1: Find the equivalent weight of NaOH • The molecular weight of NaOH is 40 g/mol. • For NaOH, the equivalent weight is the same as the molecular weight (since it releases 1 hydroxide ion, OH⁻, per molecule) Equivalent weight= 40g Step 2: Rearrange the formula to calculate the weight of NaOH: Weight of NaOH = Normality x Equivalent weight x Volume (L) Step 3: Substitute the values: • Normality = 0.5 N • Equivalent weight = 40 g/equiv • Volume = 500 mL = 0.5 L Weight of NaOH = 0.5 x 40 x 0.5 = 10g Final Answer: You need 10 grams of NaOH to prepare a 0.5 N NaOH solution in 500 mL of water.