Chapter 6 Lines and Angles | Exercise 6.3 | Class 9 Maths NCERT Question Detailed Explanation

Chapter 6 Lines and Angles | Exercise 6.3 | Class 9 Maths NCERT Question Detailed Explanation

You can contact with us -   / thestudyadda     / thestudyadda01   Telegram- https://t.me/TheStudyAdda PLAYLIST Class 9 NCERT Math All Chapterwise Solutions -    • CLASS 9th NCERT MATHS Chapterwise Sol...   Playlist Class 9 NCERT Math All Question Answer :    • Class 9th NCERT Maths | All NCERT Mat...   ✅ In this video, ✔️ Class: 9th ✔️ Subject: Maths ✔️ Chapter: 6 Lines and Angles ✔️ Topic Name: Exercise 6.3 ✔️ कक्षा: 9वीं ✔️ विषय: गणित ✔️ अध्याय: 6 रेखाएँ और कोण ✔️ विषय का नाम: अभ्यास 6.3 ✔ kaksha: 9veen ✔ vishay: ganit ✔ adhyaay: 6 rekhaen aur kon ✔ vishay ka naam: abhyaas 6.3 Question Covered :- 1. In Fig. 6.39, sides QP and RQ of ΔPQR are produced to points S and T respectively. If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ. 2. In Fig. 6.40, ∠X = 62°, ∠XYZ = 54°. If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of Δ XYZ, find ∠OZY and ∠YOZ. 3. In Fig. 6.41, if AB || DE, ∠BAC = 35° and ∠CDE = 53°, find ∠DCE. 4. In Fig. 6.42, if lines PQ and RS intersect at point T, such that ∠PRT = 40°, ∠RPT = 95° and ∠TSQ = 75°, find ∠SQT. 5. In Fig. 6.43, if PQ ⊥ PS, PQ || SR, ∠SQR = 28° and ∠QRT = 65°, then find the values of x and y. 6. In Fig. 6.44, the side QR of ΔPQR is produced to a point S. If the bisectors of ∠PQR and ∠PRS meet at point T, then prove that ∠QTR = 1/2∠QPR. 1. आकृति 6.39 में, ΔPQR की भुजाएँ QP और RQ क्रमशः बिन्दुओं S और T तक बढ़ाई गई हैं। यदि ∠SPR = 135° और ∠PQT = 110° है, तो ∠PRQ ज्ञात कीजिए। 2. आकृति 6.40 में, ∠X = 62°, ∠XYZ = 54° है। यदि YO और ZO क्रमशः Δ XYZ के ∠XYZ और ∠XZY के समद्विभाजक हैं, तो ∠OZY और ∠YOZ ज्ञात कीजिए। 3. आकृति 6.41 में, यदि AB || DE, ∠BAC = 35° और ∠CDE = 53° है, तो ∠DCE ज्ञात कीजिए। 4. आकृति 6.42 में, यदि रेखाएँ PQ और RS बिंदु T पर इस प्रकार प्रतिच्छेद करती हैं कि ∠PRT = 40°, ∠RPT = 95° और ∠TSQ = 75° है, तो ∠SQT ज्ञात कीजिए। 5. आकृति 6.43 में, यदि PQ ⊥ PS, PQ || SR, ∠SQR = 28° और ∠QRT = 65° है, तो x और y के मान ज्ञात कीजिए। 6. आकृति 6.44 में, ΔPQR की भुजा QR को बिंदु S तक बढ़ाया गया है। यदि ∠PQR और ∠PRS के समद्विभाजक बिंदु T पर मिलते हैं, तो सिद्ध कीजिए कि ∠QTR = 1/2∠QPR है। 1. aakrti 6.39 mein, dpqr kee bhujaen qp aur rq kramashah binduon s aur t tak badhaee gaee hain. yadi ∠spr = 135° aur ∠pqt = 110° hai, to ∠prq gyaat keejie. 2. aakrti 6.40 mein, ∠x = 62°, ∠xyz = 54° hai. yadi yo aur zo kramashah d xyz ke ∠xyz aur ∠xzy ke samadvibhaajak hain, to ∠ozy aur ∠yoz gyaat keejie. 3. aakrti 6.41 mein, yadi ab || dai, ∠bach = 35° aur ∠chdai = 53° hai, to ∠dchai gyaat keejie. 4. aakrti 6.42 mein, yadi rekhaen pq aur rs bindu t par is prakaar pratichchhed karatee hain ki ∠prt = 40°, ∠rpt = 95° aur ∠tsq = 75° hai, to ∠sqt gyaat keejie. 5. aakrti 6.43 mein, yadi pq ⊥ ps, pq || sr, ∠sqr = 28° aur ∠qrt = 65° hai, to x aur y ke maan gyaat keejie. 6. aakrti 6.44 mein, dpqr kee bhuja qr ko bindu s tak badhaaya gaya hai. yadi ∠pqr aur ∠prs ke samadvibhaajak bindu t par milate hain, to siddh keejie ki ∠qtr = 1/2∠qpr hai. Tag;- ncert class 9 maths chapter 3,maths cbse class 9,class 9 maths coordinate geometry ex 3.1,class 9 maths chapter 3, class 9 maths,chapter 3 coordinate geometry,maths for class 9,coordinate geometry class 9,class 9 maths chapter 3,class 9 maths chapter 3 ncert solutions,coordinate geometry,class 9 maths in hindi,class 9 maths english, Disclaimer: "This video is for educational and informational purposes only and is not intended to infringe on any copyrights. If you believe that this video has used any copyrighted material in a way that constitutes copyright infringement, please contact us at cand we will take appropriate action."