RPF Constable 2025 | 6 March 2025 Shift 1 Maths Answer Key & Solutions by Prakash Sir

RPF Constable 2025 | 6 March 2025 Shift 1 Maths Answer Key & Solutions by Prakash Sir

RPF Constable 2025 | 6 March 2025 Shift 1 Maths Answer Key & Solutions by Prakash Sir #rpfconstable #rpf #rpfconstable2025 #rrbgroupd #rrbntpc #rrbgroupd2025 #rrbalp #rrbntpc2025 #prakashsir #railwayexam ЁЯЯв https://play.google.com/store/apps/de... ЁЯЯв WhatsApp Enquiries : 8802279688 ЁЯФ╡ FACEBOOK PAGE : ┬а┬а/┬аprakashawasthibhu┬а┬а ЁЯМР TWITTER : https://twitter.com/prakashsirmaths?s=09 ЁЯЯвTELEGRAM :-https://t.me/prakashsirmathsyoutube RPF Constable 2025 | 6 March 2025 Shift 1 Maths Answer Key & Solutions RPF Constable 2025 | March 6, 2025 Shift 1 Maths Paper Solution by Prakash Sir RPF Constable 2025 Answer Key RPF Constable 2025 Maths Solved Paper RPF Constable 2025 Exam Analysis RPF Constable 2025 Maths Questions RPF Constable CBT 2025 Answer Key Railway Protection Force Exam 2025 RPF Constable 2025 Shift-wise Answer Key RPF Constable Maths Answer Key 6 March 2025 Shift 1 Maths Solutions RPF Constable 2025 Shift 1 Answer Key RPF Constable Maths Question Paper RPF Constable 2025 Paper Solution RPF Exam Answer Key 2025 тВ╣20 рдореЗрдВ 1 ┬╜ рд▓реАрдЯрд░ рдХреАрдордд рд╡рд╛рд▓реЗ 60 рд▓реАрдЯрд░ рджреВрдз рдореЗрдВ рдХрд┐рддрдирд╛ рдкрд╛рдиреА рдорд┐рд▓рд╛рдпрд╛ рдЬрд╛рдирд╛ рдЪрд╛рд╣рд┐рдП рдХрд┐ тВ╣10 тЕФ рдкреНрд░рддрд┐ рд▓реАрдЯрд░ рдХреАрдордд рдХрд╛ рдорд┐рд╢реНрд░рдг рдкреНрд░рд╛рдкреНрдд рд╣реЛ? How much water must be added to 60 litres of milk costing тВ╣ 20 for 1 ┬╜ litre to get a mixture costing тВ╣ 10 тЕФ per litre? рд╡рд╣ рд╕рдмрд╕реЗ рдЫреЛрдЯреА рд╕рдВрдЦреНрдпрд╛ рдЬреНрдЮрд╛рдд рдХреАрдЬрд┐рдП рдЬрд┐рд╕реЗ 36, 49, 54 рдпрд╛ 70 рд╕реЗ рднрд╛рдЧ рджреЗрдиреЗ рдкрд░ рдХреНрд░рдорд╢рдГ 19, 32, 37 рдФрд░ 53 рд╢реЗрд╖рдлрд▓ рдкреНрд░рд╛рдкреНрдд рд╣реЛред Find the smallest number which when divided by 36, 49, 54, or 70 leaves remainders 19, 32, 37, and 53 respectively. рдЕрджреНрд╡реИрдд 19 рдШрдВрдЯреЗ рдореЗрдВ 947 km рджреВрд░ рдХрд╛рдирдкреБрд░ рдкрд╣реБрдБрдЪрддрд╛ рд╣реИред 6 рдШрдВрдЯреЗ рддрдХ рдЙрд╕рдХреА рдкреНрд░рд╛рд░рдВрднрд┐рдХ рдЪрд╛рд▓ 38 km/hr рдереАред рдЕрдЧрд▓реЗ 70 km рддрдХ рдЙрд╕рдХреА рдЪрд╛рд▓ 35 km/hr рдереАред 19 рдШрдВрдЯреЗ рдХреЗ рдирд┐рд░реНрдзрд╛рд░рд┐рдд рд╕рдордп рдореЗрдВ рдХрд╛рдирдкреБрд░ рдкрд╣реБрдБрдЪрдиреЗ рдХреЗ рд▓рд┐рдП рдЙрд╕реЗ рдЕрдм рдХрд┐рд╕ рдЪрд╛рд▓ рд╕реЗ рдпрд╛рддреНрд░рд╛ рдХрд░рдиреА рд╣реЛрдЧреА? Advait reaches Kanpur, which is 947 km away, in 19 hours. For 6 hours his initial speed was 38 km/hr. For the next 70 km his speed was 35 km/hr. To reach Kanpur in the scheduled time of 19 hours, at what speed should he travel now?